University of Central Florida (UCF) AST2002 Astronomy Final Practice Exam

Question: 1 / 400

What would be the expected velocity of a galaxy located 100 million light-years away, given Hubble's constant is 22 kilometers per second per million light-years?

Away from us at 2,200 km/s.

To determine the expected velocity of a galaxy based on its distance from us and Hubble's constant, we can use Hubble's Law. Hubble’s Law states that the recessional velocity of a galaxy (the speed at which it is moving away from us) is directly proportional to its distance from us. The relation can be expressed as:

\[ v = H_0 \times d \]

where \( v \) is the velocity, \( H_0 \) is Hubble's constant, and \( d \) is the distance to the galaxy.

In this scenario, Hubble's constant is given as 22 kilometers per second per million light-years, and the distance to the galaxy is 100 million light-years.

To find the velocity, we can plug the values into the formula:

\[ v = 22 \, \text{km/s/Mly} \times 100 \, \text{Mly} \]

\[ v = 22 \, \text{km/s/Mly} \times 100 \]

\[ v = 2200 \, \text{km/s} \]

This calculation shows that the expected velocity is 2200 kilometers per second. The galaxy would therefore be moving away

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Away from us at 22 km/s.

Away from us at 220 km/s.

Away from us at 220,000 km/s.

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